Combinatorics
Nobody has attempted this. A complete proof or refutation takes the whole bounty.
Formal statement
Proof target
import FormalConjectures.ErdosProblems.«893»
import TaskSupport
namespace Bounty
theorem target : fcTypeOfName% "Erdos893.erdos_893" := by
sorry
end Bounty
Original conjecture (Lean type)
True ↔ Filter.Tendsto (fun n => ↑(Erdos893.f (2 * n)) / ↑(Erdos893.f n)) Filter.atTop Filter.atTopOriginal conjecture source: FormalConjectures/ErdosProblems/893.lean
References
Something wrong with this formalization?
A statement that does not faithfully capture the original conjecture is the one real risk here, so we would rather hear about it early - before someone spends weeks on it.
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