Combinatorics
Nobody has attempted this. A complete proof or refutation takes the whole bounty.
Formal statement
Proof target
import FormalConjectures.GreensOpenProblems.«39»
import TaskSupport
namespace Bounty
theorem target : fcTypeOfName% "Green39.green_39" := by
sorry
end Bounty
Original conjecture (Lean type)
True ↔
Filter.Tendsto
(fun p =>
have k := (↑p).sqrt;
have c := 100 * k;
↑(Green39.proportionCoverable (↑p) k c))
Filter.atTop (nhds 1)Original conjecture source: FormalConjectures/GreensOpenProblems/39.lean
References
Something wrong with this formalization?
A statement that does not faithfully capture the original conjecture is the one real risk here, so we would rather hear about it early - before someone spends weeks on it.
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